4 adults and 2 child tickets cost $47, 1 adult and 3 child tickets cost $25.50. So, Emma has 15 notes of £20, 8 notes of £5 in her handbag.ġ0. Subtracting equation (i) from equation (ii) The total number of notes in the handbag is 23.Īs per the second condition in the question, Let us take the number of £20 notes as x, £5 notes as y. The amount of money she has in the bag is £340.00. Emma has 23 notes of £20 and £5 in her handbag. So, the number of children attended the small fair is 1500, the number of adults attended the fair is 700.ĩ. Putting x = 2200 – y in the second equation. The admission fee at a small fair is $1.50 for children and $4.00 for adults and the total amount collected is $5050. The total number of people who attended the fair is 2200. Let us take the number of children who attended the fair as x, the number of adults who attended the fair as y. How many children and how many adults attended? Solution: On a certain day, 2200 people enter the fair and $5050 is collected. The admission fee at a small fair is $1.50 for children and $4.00 for adults. Find the numbers? Solution:Īccording to the first condition in the question,Īccording to the second condition in the question,Ĩ. The difference between the two numbers is 4.ħ. The sum of two numbers is 28 and their difference is 4. Therefore, the speed of boat is 12 miles/hour, current is 3 miles/hour.Ħ. The linear equation for upstream speed is x – y = 9 - (i) The boat can travel 30 miles downstream in 2 hours.ĭownstream speed = (Downstream distance) / (Downstream time) Upstream speed = (Upstream distance)/(Upstream time) The boat can travel 27 miles upstream in 3 hours Let x be the speed of the boat (without current), let y be the speed of the current. Find the speeds of the boat and the current? Solution: The same boat can travel 30 miles downstream in 2 hours. It takes 3 hours for a boat to travel 27 miles upstream. One number is three times the other number.ĥ. One number is three times the other number. The second condition is the difference between the numbers is 60.Ĥ. The first condition is the first number is six times the second number. Let the first number be x, the second number be y. The difference between the numbers is 60. The first number is six times the second number. So, costs of one bush is $23, and of one tree is $47.ģ. Subtract equation (iii) from equation (i) The second condition is he bought 6 bushes and 2 trees and totaled $232 The first condition is he bought 13 bushes and 4 trees from the nursery for the first time and its total cost was $487 Let the cost of each bush be x, one tree is y. What were the costs of one bush and of one tree? Solution:
The bills do not list the per-item price. For the second time, he bought 6 bushes and 2 trees and totaled $232. Mahesh bought 13 bushes and 4 trees from the nursery for the first time and its total cost was $487. Therefore, the required 2 digit number is 25.Ģ. If the numbers are reversed, then the number can be written as 10y + x The sm of two digits of the number as can be written as 10x + y
If the numbers are reversed, then the number is increased by 27. The sum of the digits of a two-digit number is 7. Solution:Īccording to the data provided in the question, When the digits are reversed, the number is increased by 27. Also, have a look at Worksheet on Simultaneous Linear Equations and prepare well for the exam.ġ. So, practice all the questions from the Simultaneous Linear Equations Worksheet and develop your skills. It contains a number of examples of Simultaneous Linear Equations. Our System of Linear Equations Word Problems Worksheet is helpful to improve your preparation levels. Students who want to get complete knowledge on Simultaneous Linear Equations Word problems can check this Worksheet on Problems on Simultaneous Linear Equations.